WebThere exist built-in functions in MATLAB to convert subscript indices to linear indices, and vice versa: sub2ind and ind2sub respectively. You can manually convert the subscripts (r,c) to a linear index by. idx = r + (c-1)*size(M,1) To understand this, if we are in the first column then the linear index will simply be the row index. WebA linear index allows use of a single subscript to index into an array, such as A(k).MATLAB ® treats the array as a single column vector with each column appended to the bottom of the previous column. Thus, linear indexing numbers the elements in the columns from top to bottom, left to right.
Noteworthy Differences from other Languages · The Julia …
WebOct 26, 2024 · Harrell's C-index (also known as the concordance index) introduced in Harrell et al. 1982, is a goodness of fit measure for models which produce risk scores. It … WebAug 6, 2012 · Sorted by: 74. For a zero-based index, the two operations are, where width is the width of the structure: row = index / width column = index % width. Those are for C using integers, where the division rounds down and the % modulo operator gives the remainder. If you're not using C, you may have to translate to the equivalent operations. small residential solar power system
How to stop a for loop after comparing one value from an array …
WebJul 4, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. WebAug 20, 2024 · Here is the problem. Even though both my matrix "A" and the index variable "Ind" have a size of 1000 x 500, A(Ind) becomes a column data. Therefore my C is a column data, instead of retaining its original set up of 1000 x 500. In this case, how could I do the calculation to ensure my results will be on the grid and with a size of 1000 x 500? WebAug 8, 2011 · 3. One way to go about this problem is to subtract the median and find the minimum of the absolute values of the resulting vector: [val, index] = min (abs (some_array_of_values - median (some_array_of_values))); You would get the closest value to the median as a result. This should work for finding any index of a value closest to a … small residential building design